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-4m^2+3m+8=0
a = -4; b = 3; c = +8;
Δ = b2-4ac
Δ = 32-4·(-4)·8
Δ = 137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{137}}{2*-4}=\frac{-3-\sqrt{137}}{-8} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{137}}{2*-4}=\frac{-3+\sqrt{137}}{-8} $
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